Solve the inequality. –28 4 k < 4 k < 21
1 answer:
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Answer:
Part 1 , not significant
Part II, significant
Step-by-step explanation:
Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants
(Two tailed chi square test)
We assume H0 to be true and find out expected
If H0 is true expected would be 100 white and 100 yellow
Chi square =
df = 1
p value = 0.152799
Since p value > 0.05 at 5% level we accept that the colours are equally likely
2)
Here observed are 1100 and 900
Expected 1000 & 1000
df = 1
Chi square =
p value <0.0001
These results are here statistically significant.
Answer A 5x² * ( 2y + 5)
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E =
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E =
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E =
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E =
= 2 × 0.0702
= 0.1404