Answer:
the difference of 12 and 5 is 7 so it would be 0
Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Answer:
C.
A traditional 401(k) is tax deferred because the income earned isn't taxed until the money is withdrawn.
Explanation:
A traditional 401(k) retirement plan is one that is sponsored by an employer.
When employees contribute to this plan the income is not subject to tax. Taxation is deferred till the beneficiary wants to make withdrawal.
Withdrawals are taxed at the employee's current income tax rate.
On the other hand the other popular retirement plan is the Roth 401(k) plan. It is also sponsored by the employer.
One major difference is that the Roth 401(k) is not tax deferred but are made with after tax dollars. However interest, dividends, and capital gains are tax free.
x = 3 - (3×6) + 2. We perform the operation in the bracket first.
x = 3 - 18 + 2
x = -15 + 2 = 2 -15 = -13
x = -13
Here we know that the initial velocity of the car is given by:

And the final velocity of the car is given by:

It took 3 seconds to attain the final velocity, so we have 
Therefore, the acceleration can be obtained by:


Plugging the values of the initial, final velocity and the time, we get:

So the acceleration of the car is given by:

Now we need to find the direction of the average acceleration of the car:

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

Therefore, the direction of the average acceleration of the car is
.