Question

Find the probability that a randomly

Answer 1

Answer:

$31.8\%$

Step-by-step explanation:

The area of the circle is $A=\pi r^2=\pi(4)^2=16\pi$

The area of the triangle is $A=\frac{bh}{2}=\frac{8*4}{2}=\frac{32}{2}=16$

Hence, the probability of a randomly selected point within the circle falls in the red shaded area is $\frac{16}{16\pi}=\frac{1}{\pi}\approx0.318\approx31.8\%$