Answer:
Step-by-step explanation:
x = 52° + 90° ( exterior angle of a triangle is equal to the sum of two opposite interior angles )
x = 142°
Starting from the fundamental trigonometric equation, we have
![\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}](https://tex.z-dn.net/?f=%5Ccos%5E2%28%5Calpha%29%2B%5Csin%5E2%28%5Calpha%29%3D1%20%5Ciff%20%5Csin%28%5Calpha%29%3D%5Cpm%5Csqrt%7B1-%5Ccos%5E2%28%5Calpha%29%7D)
Since
, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have
![\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}](https://tex.z-dn.net/?f=%5Csin%28%5Calpha%29%3D-%5Csqrt%7B1-%5Ccos%5E2%28%5Calpha%29%7D)
Plugging the numbers, we have
![\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}](https://tex.z-dn.net/?f=%5Csin%28%5Calpha%29%3D-%5Csqrt%7B1-%5Cdfrac%7B64%7D%7B289%7D%7D%3D-%5Csqrt%7B%5Cdfrac%7B225%7D%7B289%7D%7D%3D-%5Cdfrac%7B15%7D%7B17%7D)
Now, just recall that
![\sin(-\alpha)=-\sin(\alpha)](https://tex.z-dn.net/?f=%5Csin%28-%5Calpha%29%3D-%5Csin%28%5Calpha%29)
to deduce
![\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}](https://tex.z-dn.net/?f=%5Csin%28-%5Calpha%29%3D-%5Csin%28%5Calpha%29%3D-%5Cleft%28-%5Cdfrac%7B15%7D%7B17%7D%5Cright%29%3D%5Cdfrac%7B15%7D%7B17%7D)
30 days
Step-by-step explanation:
720/24
30
hope it helps ,pls mark me as brainliest
Answer:
It's (very roughly) 12 hours from one high tide to the next, and of course the same for low tides. That's because the tides produced when the Moon is directly overhead or in the opposite direction are the same. Same with two low tides, since there are two tides a day (both low and high).