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2 years ago

Which expression is equivalent to sin(2x) cosx

Mathematics

1 answer:

Vsevolod [243]2 years ago

7 0

Answer:

$2sin(x)cos^2(x)$

Step-by-step explanation:

To solve the problem, you must expand the trigonometric expression using the information given.

$sin(2x)cosx\\sin(2x)\\=2sin(x)\\=2sin(x)cos^2(x)$

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2. In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviati

Kobotan [32]

Answer: $85,000

Step-by-step explanation:

Given : In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviation of $12,000.

$\mu_M=40,000\ \ ;\sigma_M=12,000$

Female earnings have a mean of $45,000 per year and a standard deviation of $18,000.

$\mu_F=45,000\ \ ;\sigma_F=18,000$

If C denote the combined earnings for a randomly selected couple.

Then, the mean of C will be :-

$\mu_c=\mu_M+\mu_F\\\\=40,000+45,000=85,000$

Hence, the mean of C = $85,000

8 0

3 years ago

Find the difference. <br> - 4 1/9 - 7 2/3<br> **Answer should be a fraction**

olganol [36]

Answer:

your answer is

$- 11 \frac{7}{9}$

4 0

2 years ago

Use the formula v=u+at <br>calculate v when:<br>u=10, a=3, t=2.5

Ksenya-84 [330]

Answer:

Step-by-step explanation:

$v = 10 + 3 \times 2.5 \\ v = 10 + 7.5 \\ v = 17.5$

This is your answer :))

7 0

3 years ago

Read 2 more answers

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

3 years ago

PLS HELP WILL GIVE BRAINLIEST

Vanyuwa [196]

Answer:

The correct answer is the last choice. It travels for 2 hours, then stops for 1 hour, and finally travels again for 2 hours.

Step-by-step explanation:

In the first segment of the trip, the car goes from 0 to 2 hours and the line is moving up. Therefore, it traveled for 2 hours.

In the second segment, the line went straight horizontal for 1 hour. That means the distance didn't change, in other words, it didn't move.

In the last segment, it moved up again for 2 hours.

7 0

3 years ago

Read 2 more answers