pls help i hate math. three forces act on an object. one force pulls right with 60n. the second pulls left with 30n. the third p
1 answer:
You might be interested in
Answer:
Here's what I get.
Step-by-step explanation:
Assume the diagram is like the one below.
Segments AB, BC, and CH are transversals to the sides of the pool table.
BC is also a transversal to AB and CH.
a. Angles we can be sure about
∠ABC — interior opposite angles of transversal BC
∠CBH — interior opposite angles of transversal BC
∠BHC — interior angles of triangle BHC
∠ABK — alternate exterior angles of transversal BC
∠CHG — complementary to ∠CGH
b. Sets of congruent angles
∠ABC ≅ ∠BCH = 66° — interior opposite angles of transversal BC
∠CBH ≅ ∠BCE = 57° — interior opposite angles of transversal BC
∠BHC ≅ ∠GCH = 57° — interior opposite angles of transversal CH
∠ABK ≅ ∠GCH = 57° — alternate exterior angles of transversal BC
One set of congruent angles is {∠ABC, ∠BCH}
Another set is {∠ABK, ∠BCE, ∠BHC, ∠CBH, ∠GCH}
c. Alternate interior angles
Alternate interior angles are a pair of angles on the inner sides of the parallel lines but on opposite sides of the transversal.
The sets of alternate interior angles are {∠ABC, ∠BCH}, {∠ ABC, ∠BCD} {∠BCE, ∠CBH}, {∠CHJ, ∠GCH}
d. Corresponding angles
Corresponding angles are a pair of angles on the same side of parallel lines and on the same side of the transversal.
The diagram has no corresponding angles.
