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bekas [8.4K]
3 years ago
12

Two boxes are similar, the length of the side of the small box is 4cm, the length of the side of the big box is 16cm. The volume

of the big box is 320cm3 what is the volume of the small box?
Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

80cm^3

Step-by-step explanation:

16/4 = 4

This means that the scale factor = 4

320cm^3 = Volume of BB

BB/4 = Volume of SB

320/4 = 80

Therefore, the volume of the small box = 80cm^3.

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How much does a whole herd of yak’s weight?<br> A.) 33 ounces <br> B.) 33 pounds<br> C.) 33 tons
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Paper clips are sold in boxes of 1000.
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Answer:

6.5%

Step-by-step explanation:

1000 in a box and he orders 5 boxes.

1000x5= 5000

So he orders 5000 paper clips

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3 years ago
An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted t
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Answer:

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

Step-by-step explanation:

An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the actual MPG for this van since it is believed that the van has an incorrect manufacturer's MPG rating:

At the null hypothesis, we test if the mean is the same, that is:

H_0: \mu = 59.5

At the alternate hypothesis, we test that it is different, that is:

H_a: \mu \neq 59.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

59.5 is tested at the null hypothesis:

This means that \mu = 59.5

After testing 250 vans, they found a mean MPG of 59.2. Assume the population standard deviation is known to be 1.9.

This means that n = 250, X = 59.2, \sigma = 1.9

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{59.2 - 59.5}{\frac{1.9}{\sqrt{250}}}

z = -2.5

Pvalue of the test and decision:

The pvalue of the test is the probability of finding a mean that differs from 59.5 by at least 0.3, which is P(|Z|>-2.5), which is 2 multiplied by the pvalue of Z = -2.5.

Looking at the z-table, Z = -2.5 has a pvalue of 0.0062

2*0.0062 = 0.0124

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

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