Two boxes are similar, the length of the side of the small box is 4cm, the length of the side of the big box is 16cm. The volume
1 answer:
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If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22