Question

Plot the foci of the hyperbola represented by the equation x^2/625 − y^2/3600 =1 100pts

Answer 1

The attached image represents the foci of the hyperbola

How to determine the foci?

The equation of the hyperbola is given as:

$\frac{x^2}{625} - \frac{y^2}{3600} = 1$

Rewrite as:

$\frac{x^2}{25^2} - \frac{y^2}{60^2} = 1$

A hyperbola is represented as:

$\frac{(x - h)^2}{b^2} - \frac{(y - k)^2}{a^2} = 1$

This means that:

h = 0

k = 0

b = 25

a = 60

Next, calculate c the distance from the center to the focus using:

$c = \sqrt{a^2 -b^2}$

This gives

$c = \sqrt{60^2 -25^2}$

Evaluate

$c = \pm \sqrt{2975}$

This means that:

Foci = (0, -√2975) and (0, √2975)

See attachment for the hyperbola and the foci

Read more about hyperbola at:

brainly.com/question/16735067

#SPJ1