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Temka [501]
2 years ago
7

What value of k transforms the graph of f(x)=0.5x+3 into graph g? Describe the transformation.

Mathematics
1 answer:
lozanna [386]2 years ago
8 0

Using translation concepts, the values of k are given as follows:

  • 7. k = 3.
  • 8. k = -2.
  • 9. k = 2.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem:

  • In graph 7, g(x) is a shift up of 3 units of f(x), hence k = 3.
  • In graph 8, g(x) is a shift left of 2 units of f(x), that is, g(x) = f(x + 2), hence k = -2.
  • In graph 9, g(x) is a vertical stretch by a factor of 2 of f(x), that is, g(x) = 2f(x), hence k = 2.

More can be learned about translation concepts at brainly.com/question/27885240

#SPJ1

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A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
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Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

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