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3 years ago

How do you do 32y + 12y

Mathematics

2 answers:

Papessa [141]3 years ago

6 0

Answer:

44y

Step-by-step explanation:

Just ignore the y since they have the same variable. If they have common variables then just ignore the variable and look at the coefficient, the number next to the variable. 32+12 is equal to 44 so the answer is 44y.

mestny [16]3 years ago

3 0

Hi there!

Answer:

=44y

*The answer must have a positive sign.*

Step-by-step explanation:

<h2>Lesson: Distributive Property</h2>

Distributive property: →→→→ $a(b+c)=ab+ac$

First, you add by the numbers from left to right.

$32+12=44$

Final answer is 44y.

I hope this helps you!

Have a nice day! :)

-Charlie

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Read 2 more answers

If y varies directly as x^2 and y=12 when x=2, find y when x=5

Shkiper50 [21]

$y=ax^2\\\\y=12\ \ \ and\ \ \ x=2\ \ \ \Rightarrow\ \ \ 12=a\cdot 2^2\ \ \ \Rightarrow\ \ \ a= \frac{4}{12}= \frac{1}{3} \\\\y=\frac{1}{3} x^2\\\\x=5\ \ \ \Rightarrow\ \ \ y=\frac{1}{3} \cdot5^2=\frac{25}{3} =8\frac{1}{3}$

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3 years ago

What is the sum of all positive integers less than 300 which are divisible by 3

drek231 [11]

Answer:

14,850

Step-by-step explanation:

You need the sum of

3 + 6 + 9 + 12 + ... + 294 + 297

Factor out a 3 from the sum

3 + 6 + 9 + 12 + ... + 294 + 297 = 3(1 + 2 + 3 + 4 + ... + 98 + 99)

You need to add all integers from 1 to 99 and multiply by 3.

The sum of all consecutive integers from 1 to n is:

[n(n + 1)]/2

The sum of all consecutive integers from 1 to 99 is

[99(99 + 1)]/2

The sum you need is 3 * [99(99 + 1)]/2

3 + 6 + 9 + 12 + ... + 294 + 297 =

= 3 * [99(99 + 1)]/2

= 3 * [99(100)]/2

= 3 * 9900/2

= 14,850

4 0

3 years ago