What is the simplified form of the quantity 1 over x plus 1 over y all over 1 over x minus 1 over y

Mathematics

2 answers:

Ne4ueva [31]1 year ago

7 0

X plus y over y minus X

monitta1 year ago

4 0

Answer:

the answer is x plus y over x minus y

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a square sandbox has an area of 42 squareft what is the approximate perimeter of the sandbox to the nearest hundredth

Ugo [173]

The area of a square is its side length squared. So the side length of the square squared is 42, so the side length of the square is sqrt(42). The perimeter of the square is 4 times the side length, or 4sqrt(42), which is approximately 25.92.

3 0

3 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)