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Eduardwww [97]
3 years ago
10

What are the first three terms of the sequence defined by the following equation?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0

a_n=6+(n-1)(-4)=6+(n)(-4)+(-1)(-4)=6-4n+4=10-4n

Put n = 1, n = 2 and n = 3 to the equation:

a_1=10-4(1)=10-4=6\\\\a_2=10-4(2)=10-8=2\\\\a_3=10-4(3)=10-12=-2

<h3>Answer: A. 6, 2, -2.</h3>
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

First term = 6 + (1 -1)(-4) = 6 + 0 = 6.

2nd term = 6 + (2 - 1)(-4) = 6 + (-4) = 2.

a3 = 6 + (3 - 1)(-4) =  6 + (-8) = -2.


Its Choice A.

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Answer:

The absolute value can be graphed using the points around the vertex (-2, 0), (-4, 2), (-3, 1), (-1, 1), (0, 2).

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<u>Step-by-step explanation:</u>

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<u>The equation can be framed as :</u>

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