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Eduardwww [97]
3 years ago
10

What are the first three terms of the sequence defined by the following equation?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0

a_n=6+(n-1)(-4)=6+(n)(-4)+(-1)(-4)=6-4n+4=10-4n

Put n = 1, n = 2 and n = 3 to the equation:

a_1=10-4(1)=10-4=6\\\\a_2=10-4(2)=10-8=2\\\\a_3=10-4(3)=10-12=-2

<h3>Answer: A. 6, 2, -2.</h3>
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

First term = 6 + (1 -1)(-4) = 6 + 0 = 6.

2nd term = 6 + (2 - 1)(-4) = 6 + (-4) = 2.

a3 = 6 + (3 - 1)(-4) =  6 + (-8) = -2.


Its Choice A.

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The measure of angle X is 18 more than three times the measure of its complement. Find the measure of angle X. 
Ymorist [56]
The complement of an angle is 90 minus the angle, or

90 - x = complement angle

if x is 18 more than 3 times it's complement, then

x = 3(complement angle) + 18

We can substitute "90 - x" for the "complement angle" in the second equation:

x = 3(90 - x) + 18

distribute the 3 to the 90 and the x

x = 270 - 3x + 18 

add 3x to both sides

4x = 270 - 18
4x = 252
x = 63

the measure of angle x is 63 degrees
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2 years ago
Sam earns $54 275 in a year.
weqwewe [10]

Answer:

he would pay $8,293.5 in income tax.

b:

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5 0
3 years ago
What is 3+x if x = 2. Give answer but do not give detailed explanation. Thank you.
goblinko [34]

Answer: 3 + x = 5.

Step-by-step explanation:

2 + 3 = 5, if 2 = x. Hope this helps :)

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!! PLEASE ANSWER A AND B! GIVING AWAY 13 POINTS
telo118 [61]
According to google A. Would be 2.375 or as a fraction it would be 2 3/8
5 0
3 years ago
Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0
2 years ago
Read 2 more answers
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