Graph this equation y=x^2-6x-3
1 answer:
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Answer:
vertex = (- 1, 1 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = x² + 2x + 2 ← is in standard form
with a = 1 and b = 2 , then
x = - = - 1
substitute x = - 1 into the equation for y- coordinate of vertex
y = (- 1)² + 2(- 1) + 2 = 1 - 2 + 2 = 1
vertex = (- 1, 1 )
5x - 12y = 24 - it's a standard form of equation of a line
The slope-intercept form: y = mx + b
m - slope
b - y-intercept.
Convert the standard form to the slope-intercept form:
<em>subtract 5x from both sides</em>
<em>divide both sides by (-12)</em>
Answer: