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castortr0y [4]
2 years ago
10

Find the value of 6a+5b when a = 4.2 and b = -1.9

Mathematics
1 answer:
anastassius [24]2 years ago
5 0

Answer:

the answer is -5.3 hopes this helps

Step-by-step explanation:

6a+5b=?

6(4.2)+5(-1.9)=?

6(4.2)= 25.2

5(-1.9)= -9.5

4.2 - 9.5= -5.3

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What is the value of the expression. -8-(-3) <br> = -8 blank 3 <br> = blank
Mashutka [201]

Answer:

Step-by-step explanation:

-(-)=+

so  -8-(-3)=-8+3

=-5

6 0
3 years ago
Solve the equation for w<br> 7w + 18 = 10w + 24
DochEvi [55]

Answer:

The answer is -2.

Step-by-step explanation:

7w + 18 = 10w + 24

7w = 10w + 6

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6 0
3 years ago
Read 2 more answers
What is the answer to 7 7/8 - 3 1/4=
GenaCL600 [577]
4 5/8

Take 7 - 3 = 4 as the whole number 
Then take 1/4 change it to 5/8 by multiplying 1 x 2 = 2 then 4 x 2 = 8  = 2/8 
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Answer 4 5/8
8 0
4 years ago
The parabola y=x^2 is reflected across the x axis and then scaled vertically by a factor of 1/8.
tekilochka [14]

ANSWER

The new equation is:

y =  -  \frac{1}{8}  {x}^{2}

EXPLANATION

The given parabola has equation,

y =  {x}^{2}

This is the parent function.

When we reflect this parabola in the x-axis and then scaled vertically by a factor of 1/8.

The new equation becomes:

y =  -  \frac{1}{8}  {x}^{2}

3 0
3 years ago
What is the length of BC? If your answer is not an integer, leave it in simplest radical form.
IrinaVladis [17]

Answer: BC = 16√2 ft

Step-by-step explanation:

Triangle ABC is a right angle triangle. From the given right angle triangle, BC represents the hypotenuse of the right angle triangle.

With m∠W as the reference angle,

AB represents the adjacent side of the right angle triangle.

AC represents the opposite side of the right angle triangle.

To determine the length of BC, we would apply the Sine trigonometric ratio which is expressed as

Sin θ, = opposite side/hypotenuse. Therefore,

Sin 45 = 16/BC

√2/2 = 16/BC

BC = 16/(√2/2) = 16 × 2/√2

BC = 32/√2

Rationalizing the denominator, it becomes

BC = 32/√2 × √2/√2

BC = 32√2/2

BC = 16√2 ft

8 0
3 years ago
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