5x + y = 9....multiply by 7
10x - 7y = -18
----------------
35x + 7y = 63 (result of multiplying by 7)
10x - 7y = -18
----------------add
45x = 45
x = 45/45
x = 1
5x + y = 9
5(1) + y = 9
5 + y = 9
y = 9 - 5
y = 4
solution is : (1,4)
=========================
-4x + 9y = 9
x - 3y = -6 ....multiply by 4
----------------
-4x + 9y = 9
4x - 12y = -24 (result of multiplying by 4)
---------------add
- 3y = - 15
y = -15/-3
y = 5
x - 3y = -6
x - 3(5) = -6
x - 15 = -6
x = -6 + 15
x = 9
solution is : (9,5)
Y=3x-2 is the equation :^}
<span>Given:
f(0) = 2</span>
So first of all, we let x = 2012, y = 0:
<span>
Then, F(2012) = 2012 + f(0)
Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.
To add, </span>the process that relates an input to an output is called a
function.
<span>There are always three main parts of a
function, namely:
</span>Input
The Relationship
The Output
The classic way of writing a function is
"f(x) = ... ".
What goes into the function
is put inside parentheses () after the name of the function: So, f(x) shows us the
function is called "f", and "x" goes in.
What a function does with the input can be usually seen as:
<span>f(x) = x2</span><span> reveals to us that function "f" takes "x<span>" and squares
it.</span></span>
The answer i x=4/99 (fraction form )
Answer:If you would like to know what will the approximate population be after 3 years, you can calculate this using the following steps:
an initial population ... 298 quail
an annual rate ... 8%
an exponential function to model the quail population:
f = 298(1+8%)^t = 298(1+8/100)^t
f ... quail population
t ... time (years)
t = 3 years
f = 298(1+8/100)^t = 298(1.08)^3 = 375.4 quail
375.4 quail after 3 years.
