What is the sum of the first 6 terms of the sequence defined by an = 3n - 2?
1 answer:
Answer:
51
Step-by-step explanation:
when n=1
<h2><u><em>t 1=1 </em></u></h2>
<u><em>when n=2</em></u>
<u><em>t2=4</em></u>
<u><em>as first term is 1 and second term is 4 so the common difference is 3 ,for 6 term if you put this in formula for sum to the n term you will get 51 </em></u>
<u><em>t1 =1</em></u>
<u><em>d=3</em></u>
<u><em>n=6 </em></u>
<u><em>than S6=51 </em></u>
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