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dybincka [34]
4 years ago
8

Can someone help me please please please

Mathematics
1 answer:
marissa [1.9K]4 years ago
7 0
Use the Pythagorean theorem a^{2} + b^{2} = c^{2} to find the missing side length of a right triangle 

In this case, after you plug in the given numbers your equation is 12^{2} +  y^{2}  =  20^{2}

Then, Just solve that equation for y.

144 +  y^{2} = 400

x^{2} = 256

\sqrt{} y^{2}  =  \sqrt{256}

y = 16

So the answer is B, 16 cm.

I hope this helps, please feel free to ask questions if you're still confused :)
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All of the following ordered pairs satisfy the function rule y = -3x + 2 except _____.
SOVA2 [1]
(-3,12) Because you substitute the 12 in for y and -3 in for x. Then you do you order of operations and you get 12=11 which is false.
5 0
3 years ago
Given the diagram, solve for the blanks below:
zmey [24]

Answer:

AC》12

FC》6

Step-by-step explanation:

hope it helps..

have a great day.

4 0
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An account earns simple interest. Find the annual interest rate.
vlada-n [284]
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The perimeter of a rectangle is 60 cm. The ratio of length to width is 3:2. Find the length and width of the rectangle.
Hoochie [10]

Given :

  • The Perimeter of the rectangle is 60 cm
  • The ratio of the length to the width is 3:2.

To Find :

  • The Length and width of the rectangle .

⠀

Solution :

We know that,

\qquad{ \bold{ \pmb{2(Length + Breadth ) = Perimeter_{(rectangle)}}}}

Let's assume the length of the rectangle as 3x inches. and the width is 2x inches.

⠀

Now, Substituting the given values in the formula :

\qquad \dashrightarrow{ \sf{2(3x + 2x )= 60}}

\qquad \dashrightarrow{ \sf{2(6x)= 60}}

\qquad \dashrightarrow{ \sf{12x= 60}}

\qquad \dashrightarrow{ \sf{x=  \dfrac{60}{12} }}

\qquad \dashrightarrow{ \bf{x= 5}}

Therefore,

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 3x \: = 3(5) = 15 \: inches}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 2x = 2(5) = 10 \: inches}}}\:

8 0
3 years ago
Cube root 343 ^-3/ root 4 81
zlopas [31]

Answer:

$\frac{1}{1029} $

Step-by-step explanation:

$\frac{\sqrt[3]{343^{-3}}}{\sqrt[4]{81} }  $

$\boxed{\text{Property: } a^{-b}=\frac{1}{a^{b}}} $

$\frac{\sqrt[3]{\frac{1}{343^{3}} }}{\sqrt[4]{81} }  $

$\frac{\frac{\sqrt[3]{1} }{\sqrt[3]{343^3} } }{\sqrt[4]{81} }  $

$\frac{\frac{1 }{343} }{3}  $

$\frac{342 \cdot \frac{1 }{343} }{343 \cdot 3}  $

$\frac{1}{1029} $

7 0
3 years ago
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