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4 years ago

Can someone help me please please please

Mathematics

1 answer:

marissa [1.9K]4 years ago

7 0

Use the Pythagorean theorem $a^{2} + b^{2} = c^{2}$ to find the missing side length of a right triangle

In this case, after you plug in the given numbers your equation is $12^{2} + y^{2} = 20^{2}$

Then, Just solve that equation for y.

$144 + y^{2} = 400$

$x^{2} = 256$

$\sqrt{} y^{2} = \sqrt{256}$

y = 16

So the answer is B, 16 cm.

I hope this helps, please feel free to ask questions if you're still confused :)

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Subtract the following equation

Ksenya-84 [330]

Answer:

its just a black screeeeen

Step-by-step explanation:

8 0

3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

A company makes three sizes of juice bottles: small, medium, and large.

Ivahew [28]

An expression in terms of s that represents the number of large bottles is : L = $(\frac{15s}{2} /3})$

<h3>Ratio of different sizes of bottles </h3>

The company makes s small bottles every minute

let ; M represent the number of medium bottles made every minute

L represent the number of large bottles made every minute

small bottles to medium = 2 : 3

small bottles to medium = s : M

M is the unknown, so to find how many medium bottles that has been made, we must cross multiply

2M = 3s

M = $\frac{3s}{2}$ medium bottles made every minute

medium bottles to large bottles = 3 : 5

medium bottles to large bottles = M : L

where M = $\frac{3s}{2}$

The equation becomes:

3 : 5

$\frac{3s}{2}$ : L

L is the unknown, so to find how many Large bottles that has been made, we must cross multiply

3L =( $\frac{3s}{2}$ ) * 5

L = $(\frac{15s}{2} /3})$

L = ( $\frac{5}{2}$ s)

L = 2.5 s

therefore the large bottles the company makes every minute is 2.5s large bottles

we can conclude that the expression for the number of large bottles the company makes every minute with respect to s is : L = 2.5 s

Learn more about Ratio : brainly.com/question/1509142

8 0

2 years ago

-4x + 12 = 8<br><br> Solve for x

jasenka [17]

Answer:

x=1

Step-by-step explanation:

1.Move the constant to the right

2. Calculate

3. Divide both sides

4 0

3 years ago

The number of students in an school building that have the flu after t days is given by the function

gulaghasi [49]

Step-by-step explanation:

$p(0) = \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} } = \frac{800}{1 + 49} = \frac{800}{50} = 16$

$200 = \frac{800}{1 + 49 {e}^{ - 0.2t} } \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t} = 800 \\ 9800 {e}^{ - 0.2t} = 600 \\ {e}^{ - 0.2t} = \frac{3}{49} \\ ln( {e}^{ - 0.2t} ) = ln( \frac{3}{49} ) \\ - 0.2t = - 2.793 \\ t = 13.96 = 14$

6 0

3 years ago