Depends on what you're trying to study
Answer:
Part A: 2.8 miles
Part B: 16.8 miles
Step-by-step explanation:
First, solve for how many miles Ted jogged in 1 day:
Variable x = number of miles
11.2/4 = x/1
Cross multiply
11.2 × 1 = 4 × x
11.2 = 4x
Divide both sides by 4
2.8 = x
He jogged 2.8 miles every day.
To find how many miles Ted would jog in 6 days, simply multiply his miles per day by the number of days he will jog:
2.8 miles × 6 days = 16.8 miles in 6 days
If there is no equation that means that x could equal anything.
805043 would be the answer i believe
Answer:
C. ![\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The given matrices are;
![F=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]](https://tex.z-dn.net/?f=F%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D)
and
![C=\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{ccc}12(-2)+0(1)&0(-2)+-6(0)&\frac{3}{2}(-2)+7(0)\\12(0)+8(1)&0(0)+8(-6)&0(\frac{3}{2})+8(7)\\2(12)+1(1)&2(0)+1(-6)&2(\frac{3}{2})+1(7)\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%281%29%260%28-2%29%2B-6%280%29%26%5Cfrac%7B3%7D%7B2%7D%28-2%29%2B7%280%29%5C%5C12%280%29%2B8%281%29%260%280%29%2B8%28-6%29%260%28%5Cfrac%7B3%7D%7B2%7D%29%2B8%287%29%5C%5C2%2812%29%2B1%281%29%262%280%29%2B1%28-6%29%262%28%5Cfrac%7B3%7D%7B2%7D%29%2B1%287%29%5Cend%7Barray%7D%5Cright%5D)
This simplifies to;
![FC=\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
The correct answer is C
