Yes, because 5y-2x=18 and 6x=-4y-10 are both linear equations in the same variables, they form a system of linear equations.
Slope of tangent line = dy/dx = 2x+3
k is y_intercept of tangent line
2x+3 = -1
x = -2
y = (-2)^2+3(-2)+1 = -1
tangent line passes through point (-2,-1)
k = x+y
k = -2 -1
k = -3
Answer:
Step-by-step explanation:
The scenario is represented in the attached photo. Triangle ABC is formed. AB represents her distance from her base camp. We would determine BC by applying the law of Cosines which is expressed as
a² = b² + c² - 2abCosA
Where a,b and c are the length of each side of the triangle and B is the angle corresponding to b. It becomes
AB² = AC² + BC² - 2(AC × BC)CosC
AB² = 42² + 28² - 2(42 × 28)Cos58
AB² = 1764 + 784 - 2(1176Cos58)
AB² = 2548 - 1246.37 = 1301.63
AB = √1301.63
AB = 36.08 km
To find the bearing, we would determine angle B by applying sine rule
AB/SinC = AC/SinB
36.08/Sin58 = 42/SinB
Cross multiplying, it becomes
36.08SinB = 42Sin58
SinB = 42Sin58/36.08 = 0.987
B = Sin^-1(0.987)
B = 81°
Therefore, her bearing from the base camp is
360 - 81 = 279°
Answer:
The solution is (-2, 4)
Step-by-step explanation:
When finding the solution of system of equations, you need to find where both lines intersect.
In the graph shown, the light purple and dark purple line meet at (-2, 4).
Hope this helps!!
The first answer: you have to 560-200 which equals 360 then divide by 45 which equals 8 so your answers 8
The second answers: first 6.91- 1.45= 5.46 then take 5.46 and divide by 0.42 which equals 13 so your answers 13