Question

If m<2=x+8 and m<3=2x+7, what is m<2? A.57 B.25 C.30 D.33

Answer 1

Answer with explanation:

  $m\angle2=x+8\\\\m\angle 3=2 x+7\\\\ \text{Angle sum property of triangle}\\\\x+8+2 x+7+90^{\circ}=180^{\circ}\\\\3 x+15=180^{\circ}-90^{\circ}\\\\3 x=90^{\circ}-15^{\circ}\\\\3 x=75^{\circ}\\\\x=\frac{75^{\circ}}{3}\\\\x=25^{\circ}\\\\m\angle 2=25^{\circ}+8^{\circ}\\\\m\angle 2=33^{\circ}$

Option D:→ 33°

Answer 2

< 2 + < 3 + 90 = 180
< 2 = x + 8
< 3 = 2x + 7

x + 8 + 2x + 7 + 90 = 180
3x + 105 = 180
3x = 180 - 105
3x = 75
x = 75/3
x = 25

< 2 = x + 8 = 25 + 8 = 33 <==== answer is D
< 3 = 2x + 7 = 2(25) + 7 = 50 + 7 = 57