:Answer:
You may want to use an online graphing calculator to help with this problem. :)
Answer:
![\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5By%7C-2%20%E2%89%A4%20y%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%20%E2%88%9E%29%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C-4%20%E2%89%A4%20x%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-4%2C%20%E2%88%9E%29)
Explanation:
<em>See above graph</em>
I am joyous to assist you anytime.
Answer:
(p,r) = (1/3, 2/9)
Step-by-step explanation:
Here, we want to solve a system of equations
We can rewrite the second equation by dividing through by 2
So we have;
4p + 3r = 2
and
5p - 3r = 1
Add both equations:
9p = 3
p = 3/9
p = 1/3
Recall ;
5p - 3r = 1
3r = 5p - 1
Substitute the value or p here
3r = 5(1/3)-1
3r = 5/3 - 1
3r = 2/3
r = 2/9
So we have the solution set as;
(p,r) = (1/3 , 2/9)
Answer:
1/2
Step-by-step explanation:
