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3 years ago

PLEASE HELP, NEED RN! (worth 50 points, you MUST answer all three questions!!)

Mathematics

2 answers:

gtnhenbr [62]3 years ago

7 0

Answer:

Can yall stop scamming it only worth 25 points

Step-by-step explanation:

harkovskaia [24]3 years ago

6 0

The Answer for #1 is found as follows:

Perimeter is the sum of all sides so...

8x+2+5x-4+9x+3=?

Group together the x's and the numbers:

8x+5x+9x+2-4+3=?

Answer = 22x+1

The Answer for #2 is found as follows:

Area of a triangle is 1/2 base times height

The bottom of the triangle is 4t, but we know t is 4 inches, so the bottom is 16.

The height is 7 times t which is 4... so the height is 28 inches.

using the formula, it will be 1/2(16)(28). The answer will be 224 inches squared.

The Answer for #2 is found as follows:

Polynomials cannot have squares or fractions. So the 2nd, 3rd, and 4th options are all not polynomials.

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An equation of a hyperbola is given.

siniylev [52]

Answer:

The vertices are $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

The foci are $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$ .

The asymptotes are $y=2x,\:y=-2x$ .

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

$\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1$ is the standard equation for a right-left facing hyperbola with center $\left(h,\:k\right)$ .

The vertices $\:\left(h+a,\:k\right),\:\left(h-a,\:k\right)$ are the two bending points of the hyperbola with center $\:\left(h,\:k\right)$ and semi-axis a, b.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and vertices $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

For a right-left facing hyperbola, the Foci (focus points) are defined as $\left(h+c,\:k\right),\:\left(h-c,\:k\right)$ where $c=\sqrt{a^2+b^2}$ is the distance from the center $\left(h,\:k\right)$ to a focus.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ $c=\sqrt{3^2+6^2}= 3\sqrt{5}$ and foci $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$

The asymptotes are the lines the hyperbola tends to at $\pm \infty$ . For right-left hyperbola the asymptotes are: $y=\pm \frac{b}{a}\left(x-h\right)+k$

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and asymptotes

$y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x$

b) The length of the transverse axis is given by $2a$ . Therefore, the lenght is 6.

c) See below.

4 0

4 years ago

1. what is the simplified form of -(x - 4)?

pav-90 [236]

1. To simplify -(x-4) change the sign on each term inside parenthesis:

-(x-4) would become -x+4

The answer is B.

2. -4xy / 3x

Cancwl the common factor out

-4xy / 3x (cross out the x's)

-4y /3

The answer is C.

4 0

3 years ago

Read 2 more answers

Paige has 3 coats: a pink one, a red one, and a white one. She has a black scarf, a gray scarf and 1 set of white gloves. Determ

IRISSAK [1]

Hi there, again! Hopefully this helps, again!

------------------------------------------------------------------------------------------------------------

Since she has 3 coats, 2 scarfs, and 1 glove:

She has 6 ways to choose a coat, a scarf, and a glove(s).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

My 6 combinations:

1.) Red coat, black scarf, white glove(s).

2.) White coat, grey scarf, white glove(s).

3.) Pink coat, black scarf, white glove(s).

4.) Red coat, grey scarf, white glove(s).

5.) White coat, black scarf, white glove(s).

6.) Pink coat, grey scarf, white glove(s).

5 0

4 years ago

Read 2 more answers

Instructions: Find the missing side of the triangle.

Marrrta [24]

Answer:

100

Step-by-step explanation:

$30 + 50 + x = 180$

$80 + x = 180$

$x = 180 - 80$

$x = 100$

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2 years ago

Can some explain how to do algebra and what's the easiest way to do it

Stolb23 [73]

Answer: The most important aspect in doing algebra is having a pen/pencil and paper in hand. It'll give you a better understanding of the question being posed.

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3 years ago