The frequency table, stem and leaf plot, and histogram are attached.
The histogram looks similar to the stem and leaf plot, except turned on its side. It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.
The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table. Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.
1) Let's evaluate that expression, given that a=4.9, b=-7, and c=-0.5
Note that we have rewritten it as a fraction so that we can easily operate. Also, we have applied here the PEMDAS order of operations, prioritizing the exponents.
Answer: 2.43m^3
Step-by-step explanation:
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2