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Tcecarenko [31]
3 years ago
15

The reciprocal of 1/20 is________.

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

0.05

Step-by-step explanation:

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Melanie has a piece of cloth 12 and 1/3 yards long. How many 3/4 yard-long pieces can be cut from the cloth?
Harrizon [31]
This is a division problem. First, get 12 1/3 into fraction form instead of mixed number form to make your life easier;  
12  \frac{1}{3} =  \frac{36}{3} +  \frac{1}{3} =  \frac{37}{3}  
  
Now, divide the two fractions. Since this is fraction division, the reciprocal is flipped and the two fractions multiplied.  
\frac{37}{3} *  \frac{4}{3} =  \frac{148}{9} = 16  \frac{4}{9}  
  
The answer from the fraction division is 16 and four-ninths, but because you need a whole number as an answer,  
the answer is 16 pieces.
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Find missing angles and variables
shutvik [7]

Answer:

e= 2x-4  

Step-by-step explanation:

the opposite of e is 2x-4.

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Find the area and perimeter of the rectangle whose sides are lengths 2x + 3 and 4x.
mote1985 [20]

The answer to this problem is 3(2x+1)

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julia-pushkina [17]

Answer:

12x^4-20x^2+32x=4x(3x^3-5x+8)

Step-by-step explanation:

<u>Common Factors</u>

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

Z=12x^4-20x^2+32x

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

Z=12x^4-20x^2+32x=4x(3x^3-5x+8)

\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}

3 0
3 years ago
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