The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
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The last name I am pretty sure of it.
Answer:
Step-by-step explanation:
Answer:
a) OA = 1 unit
b) OB = 3 units
c) AB = √10 units
Step-by-step explanation:
<u>Given function</u>:

<h3><u>Part (a)</u></h3>
Point A is the y-intercept of the exponential curve (so when x = 0).
To find the y-value of Point A, substitute x = 0 into the function:

Therefore, A (0, 1) so OA = 1 unit.
<h3><u>Part (b)</u></h3>
If BC = 8 units then the y-value of Point C is 8.
The find the x-value of Point C, set the function to 8 and solve for x:

Therefore, C (3, 8) so Point B is (3, 0). Therefore, OB = 3 units.
<h3><u>Part (c)</u></h3>
From parts (a) and (b):
To find the length of AB, use the distance between two points formula:


Therefore:




