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Nina [5.8K]
2 years ago
5

If the ordered pair (-5/2, y) lies on the graph of y=7-2x, find the value of y.

Mathematics
1 answer:
Viefleur [7K]2 years ago
8 0

The correct answer is option B which is the value of Y will be 12.

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given that:-

If the ordered pair (-5/2, y) lies on the graph of y=7-2x,

The value of Y will be calculated as:-

Y = 7 - 2x

Y = 7 - 2 ( -5/2 )

Y = 7 - ( - 5 )

Y = 7 + 5

Y = 12

Therefore the correct answer is option B which is the value of Y will be 12.

To know more about equations follow

brainly.com/question/2972832

#SPJ1

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My name is Ann [436]

Answer:

X = 4

I hope this helps

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4 0
3 years ago
Help me please i’m failing lol
nalin [4]

16) k=176 hope you get to a point were your not failing

6 0
3 years ago
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How do you factor x^3-2x^2-35x?
natima [27]
X^3 -2x^2 -35x

=x(x^2-2x-35)

=x(x-7)(x+5)
5 0
3 years ago
Read 2 more answers
Melania has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. her office job pay
bulgar [2K]
Lets x = # of hours Melania  works at <span>office clerk
and y = </span># of hours Melania  works as a <span>cashier

x + y = 38 so x = 38 - y
13x + 9.25y = 434

substitute </span> x = 38 - y into 13x + 9.25y = 434

13x + 9.25y = 434
13(38 - y) + 9.25y = 434
494 - 13y + 9.25y = 434
                  -3.75y = -60
                          y = 16
x = 38 - y so x = 38 - 16 = 22

answer
Melania  works at office clerk = 22 hours
Melania  works as a cashier = 16 hours
7 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
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