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hoa [83]
3 years ago
9

29. (407) Got gbvttvgbybtvrcrcgbbgbgbtvfvtvybgbtvtcvfbghnvgvffvhbjngbvfvfgb

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
4 0

Answer:

really what even is this

Step-by-step explanation:

this makes no sense

Mumz [18]3 years ago
4 0
I do not get this question
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Simplify the expression by combining like terms.<br> 7.2(x + 3) + 4(x - 3)
siniylev [52]

Answer: 11.2x -9.6

Step-by-step explanation:

7.2(x + 3) + 4(x - 3) -  12       - 7.2* (x + 3) + + 4*(x - 3) then

7.2x + 21.6 + 4x -  12  - Combining like terms 7.2x+ 4x  and numbers + 21.6-  12          

7.2x + 4x +21.6 -12       Then we have

11.2x -9.6

3 0
3 years ago
Teresa drove 936 miles in 13 hours. At the same rate, how many miles would she drive in 9 hours?
grandymaker [24]
If Teresa drove 936 miles in 13 hours, this would mean she would have driven 72 miles every hour. 72 times 9 equals 648. After 9 hours, she would have driven 648 miles. 
5 0
3 years ago
Round the number to the thousandths place.<br><br> 47,268.568593
Tatiana [17]
47268.569 ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt
7 0
3 years ago
Draw a square with a perimeter of 16 feet
Colt1911 [192]
You need a ruler and a pencil.  Oh and paper.  Make sure that each side is equal to 4 inches.  Then make a scale of 1:12, meaning 1 inch=1 foot.
4 0
3 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
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