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Setler79 [48]
3 years ago
10

Factorise 14e-16 Please explain

Mathematics
1 answer:
rosijanka [135]3 years ago
5 0

The expression 14e - 16 is an algebraic expression, and the factored expression is 2(7e - 8)

<h3>How to factor the expression 14e - 16?</h3>

The expression is given as:

14e - 16

Express both terms as a product of 2

14e - 16 = 2 * 7e - 2 * 8

Factor out 2 in the expression

14e - 16 = 2 * (7e - 8)

Remove the product sign

14e - 16 = 2(7e - 8)

Hence, the factored expression of 14e - 16 is 2(7e - 8)

Read more about factored expressions at:

brainly.com/question/723406

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avanturin [10]

Answer:

i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}    \Rightarrow \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)4^{3} + 8^{2} + \sqrt{9}   \Rightarrow  4^{3} + 8^{2} + \sqrt{9}

iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}    \Rightarrow \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)4^{3} + 8^{2} + \sqrt{9}   \Rightarrow  4^{3} + 8^{2} + \sqrt{9}

iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

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4 years ago
G(x)=4.8x -5<br><br> I needed help finding the slope
Artist 52 [7]

Answer:

Slope is 4.8

Step-by-step explanation:

{ \tt{G(x) = 4.8x - 5}} \\

8 0
3 years ago
Read 2 more answers
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