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1 year ago

Does the graph below represent a function? why or why not?

Mathematics

2 answers:

Degger [83]1 year ago

4 0

Answer:

Step-by-step explanation:

The coordinate plane is also called a Cartesian Plane. Function. A function is a relationship where there is only one output for every input. In other words, for every value of x, there is only one value for y.

Does this help?

nataly862011 [7]1 year ago

4 0

Answer:

It is NOT a function.

Step-by-step explanation:

It does not pass the vertical line test. A vertical line can touch the graph in more than one point.

To be a function, every x can have only one y value. On this graph almost every single x has two y's. For example when x is -6, the y is 2 and also 8. Not a function.

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John bought a 4-year certificate of deposit for $9.800 that has an interest rate of 3.255 % compounding monthly

Neko [114]

Answer:

Step-by-step explanation:

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3 years ago

Given the following f(x) = 3x² + 7x³ + 8x^4; g(x) = -3x + 12x² - 5x³; and h(x) = 12x +

never [62]

The value of the function (f.h)(x) is 96x⁵ + 132x⁴ + 78x³ + 18x²

<h3>How to solve function?</h3>

f(x) = 3x² + 4x³ + 8x⁴

g(x) = -3x + 12x² - 5x³

h(x) = 12x + 6

Therefore,

(f.h)(x) = f(x).h(x)

Hence,

f(x).h(x) = (3x² + 7x³ + 8x⁴)(12x + 6)

f(x).h(x) = 36x³ + 18x² + 84x⁴ + 42x³ + 96x⁵ + 48x⁴

(f.h)(x) = 96x⁵ + 84x⁴ + 48x⁴ + 36x³ + 42x³ + 18x²

(f.h)(x) = 96x⁵ + 132x⁴ + 78x³ + 18x²

learn more on function here: brainly.com/question/7783704

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6 0

1 year ago

The number of people in a car that crosses a certain bridge is represented by the random variable X, which has a mean value μX =

Alona [7]

Let $Y$ be the total amount of money paid by any given set of passengers. If there are $X$ passengers in a car, then the driver must pay a toll of $Y=0.5X+3$ .

Then $Y$ has first moment (equal to the mean)

$E[Y]=E[0.5X+3]=0.5E[X]+3E[1]=0.5\mu_X+3=\boxed{4.35}$

and second moment

$E[Y^2]=E[0.25X^2+3X+9]=0.25E[X^2]+3E[X]+9E[1]=0.25E[X^2]+3\mu_X+9$

Recall that the variance is the difference between the first two moments:

$\mathrm{Var}[X]=E[X^2]-E[X]^2\implies E[X^2]={\sigma^2}_X+{\mu_X}^2$

$\implies E[Y^2]=0.25({\sigma^2}_X+{\mu_X}^2)+3\mu_X+9\approx19.22$

$\implies\mathrm{Var}[Y]=E[Y^2]-E[Y]^2=\boxed{0.3}$

3 0

3 years ago

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elixir [45]

Is it too late to answer ??

5 0

3 years ago

A student has a test scores of 87, 89, 94 points. What must he score on the fourth exam to have an average of at least 92 points

larisa86 [58]

Answer: He must have atleast 98 points on the next exam in order to get an average of 92 points.

Step-by-step explanation: To calculate average, you need to add all the numbers given, and divide the sum by how many numbers there are. 87 + 89 + 94 + 98 (equals 368), and divide 368 by 4. You will get the average of 92 as its result.

4 0

2 years ago