a.

By Fermat's little theorem, we have


5 and 7 are both prime, so
and
. By Euler's theorem, we get


Now we can use the Chinese remainder theorem to solve for
. Start with

- Taken mod 5, the second term vanishes and
. Multiply by the inverse of 4 mod 5 (4), then by 2.

- Taken mod 7, the first term vanishes and
. Multiply by the inverse of 2 mod 7 (4), then by 6.


b.

We have
, so by Euler's theorem,

Now, raising both sides of the original congruence to the power of 6 gives

Then multiplying both sides by
gives

so that
is the inverse of 25 mod 64. To find this inverse, solve for
in
. Using the Euclidean algorithm, we have
64 = 2*25 + 14
25 = 1*14 + 11
14 = 1*11 + 3
11 = 3*3 + 2
3 = 1*2 + 1
=> 1 = 9*64 - 23*25
so that
.
So we know

Squaring both sides of this gives

and multiplying both sides by
tells us

Use the Euclidean algorithm to solve for
.
64 = 3*17 + 13
17 = 1*13 + 4
13 = 3*4 + 1
=> 1 = 4*64 - 15*17
so that
, and so 
Answer:
324
Step-by-step explanation:
It cost 5 per game , hope it helps
Answer:
To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.
(
x
+
5
)
(
x
+
2
)
becomes:
(
x
×
x
)
+
(
x
×
2
)
+
(
5
×
x
)
+
(
5
×
2
)
x
2
+
2
x
+
5
x
+
10
We can now combine like terms:
x
2
+
(
2
+
5
)
x
+
10
x
2
+
7
x
+
10
Step-by-step explanation:
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786