The figure shows triangle PQR and line segment AB, which is parallel to QR:
2 answers:
Based on the triangle similarity theorem:
A. ΔPQR ~ ΔPAB
B. AB corresponds to QR
C. ∠A corresponds to ∠Q.
<h3>What is the Triangle Similarity Theorem?</h3>According to the triangle similarity theorem, when a segment that is parallel to one side of a triangle intersects the other two sides, the new triangle formed is therefore similar to the original triangle. This also implies that the two sides would be divided by the line segment proportionally.
Part A:
Based on the diagram given, we have:
AB is parallel to QR, therefore, the new triangle formed, triangle PAB is similar to the original triangle PQR, based on the triangle similarity theorem.
Part B:
Line segment AB corresponds to line segment QR because they lie in the same position facing angle P.
Part C:
Angle A lies in similar position with angle Q, so, angle A corresponds tp angle Q.
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