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pashok25 [27]
3 years ago
5

Quadrilateral WXYZ has the vertices W(-5, 2), X(-4, -2), Y(3, 1), and Z(2, -5). The quadrilateral is dilated by a scale factor o

f m with the origin as the center of dilation to create quadrilateral W'X'Y'Z'. Which ordered pair represents the coordinates of vertex Z'?
A. (2/m, -5/m)
B. (2m, -5m)
C. (-5m, 2m)
D. (-5/m, 2/m)
Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
I’m not sure but is maybe c
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Solve the inequality. –6 < 2x – 4 < 4
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–1 < x < 4

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Let's solve your inequality step-by-step.

−6<2x−4<4

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PLS HELP!!! There are 42 new houses being built in a neighborhood. Last month, 2/3 of them were sold. This month, 2/7 of the rem
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2 years ago
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
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Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

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3 years ago
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