Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4

Hence P(Y=1|X=3)=0.125
Here's some of the info
~<span>Evelyn has the greater mean.
~</span>Evelyn’s objects generally landed farther away from the center than Robin’s.<span>
~</span>The object is to get the objects close to the center, so Robin is winning.<span>
</span>
Answer:
second answer should be corr3ect tell em if wrong
Step-by-step explanation:
Answer Q3:
A) 2/6
This decimal would be written as 0.33333333 and on.
I don't get number 4 but I'm pretty sure its A because 12 times 12 is 144 and and you have to add the 18.
B is a variable that is as far as it can be solved