What units could you use to measure the height of a hexagonal prism?

1 answer:

4 0

The answer is centimeters (cm)

Height is 1D dimension so we cannot use cm^2 or cm^3 to measure some distance. With cm^2 we measure surface (because surface is 2D that is why it has this ^2 next to cm) and cm^3 is unit for measuring volume (volume is 3D it has height, width and thickness that is why it has ^3)
cm^4 cannot be the answer since there is no more than 3 dimensions.

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Approximate the area under the

taurus [48]

Split up the interval [0, 3] into 3 equally spaced subintervals of length $\Delta x = \frac{3-0}3 = 1$ . So we have the partition

[0, 1] U [1, 2] U [2, 3]

The left endpoint of the $i$ -th subinterval is

$\ell_i = i - 1$

where $i\in\{1,2,3\}$ .

Then the area is given by the definite integral and approximated by the left-hand Riemann sum

$\displaystyle \int_0^3 f(x) \, dx \approx \sum_{i=1}^3 f(\ell_i) \Delta x \\\\ ~~~~~~~~~~ = \sum_{i=1}^3 (i-1)^3 \\\\ ~~~~~~~~~~ = \sum_{i=0}^2 i^3 \\\\ ~~~~~~~~~~ = 0^3 + 1^3 + 2^3 = \boxed{9}$

4 0

2 years ago

Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar

ella [17]

Cost of chicken wings at Buffalo Bills = 8 wings for $7

Cost of 1 wing at Buffalo Bills = $\frac{7}{8} =0.875$

Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10

Cost of 1 wing at Buffalo Mild Wings = $\frac{10}{12}= 0.833$

Cost of chicken wings at Wingers = 20 wings at $17

Cost of 1 wing at Wingers = $\frac{17}{20}= 0.850$

Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.

8 0

3 years ago

Read 2 more answers

14+-6 what is the answer answer

Irina-Kira [14]

Answer:

the answer is 8. just think of it as subtraction. subtract +6 from +14. then you get the answer for +14+-6.

3 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$