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EleoNora [17]
3 years ago
5

Question 1 Unsaved

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

The average of the given base lengths is the length of the midsegment:

... (72 + 104)/2 = 176/2 = 88

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That would be... 936.12
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Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

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We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

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Chi square critical value for upper tail =

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80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

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3 years ago
Does anyone whatsoever have any tips for coordinate plane- like I need alot please. anything you know that helps u.
Anon25 [30]

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Quadrant I: (+ , +)

Quadrant II: (+ , -)

Quadrant III: (- , -)

Quadrant IV: (- , +)

Remember, the point is split into two parts, in which the first one is x (which signifies the placement for the horizontal line), while the other is y (which signifies the placement for the vertical line).

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Step-by-step explanation:

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