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EleoNora [17]
3 years ago
5

Question 1 Unsaved

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

The average of the given base lengths is the length of the midsegment:

... (72 + 104)/2 = 176/2 = 88

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It’s all reall numbers
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3 years ago
If the ratio of three angles of a triangle is 2:3:4 find the size of the largest angle​
Murljashka [212]
Answer: 80°

Step-by-Step Explanation:

By Angle Sum Property of a Triangle, all angles in a Triangle add up to 180°

Finding the Value of ‘x’ :-

2x + 3x + 4x = 180
5x + 4x = 180
9x = 180
x = 180/9
=> x = 20

Finding each Angle :-

2x = 2(20) = 2 * 20 = 40°
3x = 3(20) = 3 * 20 = 60°
4x = 4(20) = 4 * 20 = 80°

Hence, the Largest Angle is 80°
3 0
2 years ago
PLEASE HELP! 25 PTS!!
zubka84 [21]

Answer:

Solution given:

f(x)=\frac{x-16}{x^2+6x-40}

g(x)=\frac{1}{x+10}

now

f(x)+g(x)=\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}....(1)

now

factoring x²+6x-40

we get

x²+10x-4x-40

x(x+10)-4(x+10)

(x+10)(x-4)

now substituting in equation 1 ,we get

f(x)+g(x)=\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}

taking l.c.m

=\frac{(x-16)+(x-4)}{(x-10)(x-4)}

=now

opening bracket

\frac{x-16+x-4}{x²-10x-4x+40}

=\frac{2x-20}{x²+6x-40}

So

answer is :

B. \bold b\frac{2x-20}{x^2+6x-40}

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Step-by-step explanation:

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