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ikadub [295]
2 years ago
12

Order these numbers from least to greatest. 6.2052, 6.2, 6.75, 6.705

Mathematics
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

<u>6.2 , 6.2052 , 6.705 , 6.75</u>

Step-by-step explanation:

Least to Greatest!

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The path a character takes to navigate a level of a video game is given in the following graph.
KonstantinChe [14]

We want to find the domain for the graphed function. We will see that the correct option is A: -12 ≤ x ≤ 14

<h3>What is the domain of a function?</h3>

For a function f(x) we define the domain as the set of possible inputs that we can use in the function.

In this case, we need to see the values in the horizontal axis that the graph covers.

We can see that it goes from -12 to 14. We also can see that there are two jumps, at x = -6 and at x = 8, but these values belong to the graph (denoted by the black dot) meaning that these are in the domain.

Then the domain is:

-12 ≤ x ≤ 14

If you want to learn more about domains, you can read:

brainly.com/question/1770447

6 0
2 years ago
Am i correct? What is the answer to the next one?
podryga [215]

Answer:

With base of 3: 3^{4}

With base of 9: 9^{2}

Step-by-step explanation:

Use 3 and 9 as the base of the power.

3^{4} =81\\9^{2} =81

8 0
3 years ago
Linda is buying a new computer the shipping cost 8 percent of the purchase price if Windows computer cost $585 how much will it
Sauron [17]

Answer:

46.8

Step-by-step explanation:

8 0
3 years ago
Which property can be used to expand the expression -27x+7)
Komok [63]

Answer: I think distributive

Step-by-step explanation:

4 0
3 years ago
Pleaseeeeee help !!
umka21 [38]

A.\\-vp+40 < 95\qquad\text{subtract 40 from both sides}\\\\-vp < 55\qquad\text{change the signs}\\\\vp > -55\qquad\text{divide both sides by p}\\\\If\ p > 0\ then\ v>-\dfrac{55}{p}.\\\\If\ p < 0\ then\ v < -\dfrac{55}{p}

B>\\8w-3r=45\qquad\text{subtract 8 from both sides}\\\\-3r=-8w+45\qquad\text{change the signs}\\\\3r=8w-45\qquad\text{divie both sides by 3}\\\\r=\dfrac{8w-45}{3}

4 0
4 years ago
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