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4 years ago

12

If a statistic used to estimate a parameter is such that the mean of its sampling distribution is equal to the actual value of t

he parameter, what is the statistic said to be
-A proportion
-Random
-Biased
-Unbiased
-Varied

1 answer:

zimovet [89]4 years ago

6 0

I think the correct answer from the choices listed above is the third option. <span>If a statistic used to estimate a parameter is such that the mean of its sampling distribution is equal to the actual value of the parameter, then it is a biased estimator. Hope this answers the question.
</span>

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3 years ago

Give the values of a, b, and c needed to write the equation's general form.<br>1/4x^2+5=0

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Let's solve your equation step-by-step.

$\frac{1}{4} x^2+5=0$

For this equation: $a=0.25, b=0, c=5$

$0.25x^2 + 0x + 5 = 0$

Step 1: Use quadratic formula with $a=0.25, b=0, c=5.$

$x = \frac{-b ± \sqrt{b^2 - 4ac} }{2a}$

$x = \frac{-(0) ± \sqrt{(0)^2 -4 (0.25) (5) } }{2(0.25)}$

$x = \frac{0 ± \sqrt{-5} }{0.5}$

Answer : No Real Solutions.

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5 0

3 years ago

What is the volume of the prism below?

Triss [41]

Step-by-step explanation:

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8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

(2x + 3y) + (4x - 3y) = 11+(-5)

Maurinko [17]

Answer:

The correct option should have been $6x=6$ .

Step-by-step explanation:

Given the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

solving the expression

$\left(2x\:+\:3y\right)\:+\:\left(4x\:-\:3y\right)\:=\:11+\left(-5\right)$

Remove parentheses: (a) = a

$2x+3y+4x-3y=11-5$

Group like terms

$3y-3y+2x+4x=11-5$

Add similar elements

$6x=6$

It is clear that not a single given option is $6x=6$ . It means no option is correct. It seems you mistyped the correct options.

The correct option should have been $6x=6$ .

3 0

3 years ago