All categories

2 years ago

Can someone help me solve this.

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

8 0

$\huge\underline{Answer -}$

$\huge{\implies \: \frac{ - 2 \frac{1}{4} }{ - \frac{ 2}{3} }} \\ \\ \\ \\ \huge{\implies \: \frac{ \frac{ - 9}{4} }{ \frac{ - 2}{3} } } \\ \\ \\ \\ \huge{\implies \: - \frac{9}{4} \div (\frac{ - 2}{3} )}$

therefore , option ( 2 ) is correct.

hope helpful -,-

You might be interested in

The monthly mortgage payment on your house is $821.69. it is a 30 year mortgage at 6.5% compounded monthly. how much did you bor

Ne4ueva [31]

The amortization formula can be used to figure this.

... A = P(r/n)/(1 -(1 +r/n)^(-nt))

where A is the monthly payment, P is the amount borrowed, r is the annual interest rate, n is the number of times per year interest is compounded, and t is the number of years.

Fill in the given information, and solve for P (in either order).

... 821.69 = P(.065/12)/(1 - (1 +.065/12)^(-12*30)) ≈ 0.00632068023P

... P ≈ 130,000.25 . . . . . divide by the coefficient of P

Rounded to the nearest dollar, you borrowed $130,000.

8 0

4 years ago

What is the value of 12⁰?

vodka [1.7K]

Hello,

Answer:

12⁰ = 1

Step-by-step explanation:

We have any number with exponent 0 = 1

(a⁰) = 1

5 0

2 years ago

Read 2 more answers

Susan rolled a die 1,086 times. Which of the following would be a good estimate of the number of times she rolled the number 3 o

adell [148]

Hello!

This is a problem about probability.

What we would first do is find the theoretical probability that Susan would roll the number 3 on a die.

Assuming that this is a fair six sided die, there is only one face with the number 3, and there are 6 sides, meaning that the probability that Susan rolls a 3 would be $\frac{1}{6}$ .

Now, Susan is rolling a die 1,086, meaning that we can divide this number by 6 to find the theoretical number of times that Susan would roll the number 3 on this die.

You should get 181 times, which would be a good estimate of how many times she could roll the number 3.

Hope this helps!

4 0

3 years ago

Which relation is a function?

docker41 [41]

Answer:

The top right grid

Step-by-step explanation:

The other grids have 2 y outputs for one or more x inputs.

7 0

4 years ago

At the start of the month, the value of an investment was $73.42. By the end of the month, the value of the investment changed b

Aleonysh [2.5K]

Answer:

0.8%.

Step-by-step explanation:

Given:

At the start of the month, the value of an investment was $73.42.

By the end of the month, the value of the investment changed by a loss of $13.53.

Question asked:

What was the value, in dollars, of the investment at the end of the month?

What was the percent loss?

Solution:

At the start of the month, the value of an investment = $73.42.

Loss = $13.53.

The value, of the investment at the end of the month = The value of an investment at the start of the month - loss

The value, of the investment at the end of the month = $73.42 - $13.53

= $59.89

Thus, the value, of the investment at the end of the month is $59.89.

Now, we will find percent loss:-

$Percent\ loss = \frac{Loss}{value\ of \ investment\ at \ start}$

$=\frac{59.89}{73.42} \\=0.81\%$

Thus, percent loss on investment by the end of the month is 0.8%.

7 0

3 years ago