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dangina [55]
2 years ago
6

What is the value of 12⁰?

Mathematics
2 answers:
Zigmanuir [339]2 years ago
7 0
The value is 1
to the power of 0 results in an answer of 1
vodka [1.7K]2 years ago
5 0

Hello,

Answer:

12⁰ = 1

Step-by-step explanation:

We have any number with exponent 0 = 1  

(a⁰) = 1

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Plot 2 points on y-4=-3/4(x+1)
MA_775_DIABLO [31]
<span> x from -6 to 5, y from -10 to 10, y = -2x/3 -2). </span>
4 0
4 years ago
To secure a telephone pole, a steel cable will be attached to a ring on the pole 12 feet above the ground. If the cable is 15 fe
Inga [223]

Answer:

9 ft

Step-by-step explanation:

Pythagorean theorem:

x = the  square root of 15 square minus 12 square

x= square root of 225-144

x= square root of 81

X = 9

3 0
3 years ago
Y=−3(2.5)x
Hoochie [10]

Answer:

1. The equation represent an exponential decay

2. The rate of the exponential decay is -3×2.5ˣ·㏑(2.5)

Step-by-step explanation:

When a function a(t) = a₀(1 + r)ˣ has exponential growth, the logarithm of x grows with time such that;

log a(t) = log(a₀) + x·log(1 + r)

Hence in the equation -3 ≡ a₀, (1 + r) ≡ 2.5 and y ≡ a(t). Plugging in the values in the above equation for the condition of an exponential growth, we have;

log y = log(-3) + x·log(2.5)

Therefore, since log(-3) is complex, the equation does not represent an exponential growth hence the equation  represents an exponential decay.

The rate of the exponential decay is given by the following equation;

\frac{dy}{dx} =\frac{d(-3(2.5)^x)}{dx} = -\frac{d(3\cdot e^{x\cdot ln(2.5)})}{dx} = -3 \times 2.5^x\times ln(2.5)

Hence the rate of exponential decay is -3×2.5ˣ × ㏑(2.5)

5 0
4 years ago
Penelope invested 60% of her retirement account in stocks and 40% in gold. Penelope believes that the return to stocks over the
hjlf

Answer:

1) mean = 21, standard deviation σ = 21.9317

2) the probability that Penelope's portfolio will earn at least 12% in the next 12 months is 0.6591

Step-by-step explanation:

 Given the data in the question;

1. According to Penelope's beliefs, what are the mean rate of return and the standard deviation of return of her portfolio?

Mean μ = Return = ( 60% × 15) + ( 40% × 30 ) = 9 + 12 = 21

mean = 21

standard deviation σ = √( (0.6² × 25²) + ( 0.4² × 40² ) )

standard deviation σ = √( (0.36 × 625) + ( 0.16 × 1600 ) )

standard deviation σ = √( 225 + 256 )

standard deviation σ = √481

standard deviation σ = 21.9317

2)  What is the probability that Penelope's portfolio will earn at least 12% in the next 12 months

so we are to find P( X > 12 )

converting into standard normal variable;

⇒ P( Z  > X-μ  / σ  )

= P( Z  > ( 12-21  / 21.9317  ) )

= P( Z  > ( -9 / 21.9317  ) )

= P( Z  > -0.41 )  

FROM z-score table; P( Z  > -0.41 ) is 0.3409

P( X > 12 ) = 1 - 0.3409

P( X > 12 ) = 0.6591

Therefore,  the probability that Penelope's portfolio will earn at least 12% in the next 12 months is 0.6591

3 0
3 years ago
Help please and hurry I need it rn even if you are not sure
Lesechka [4]

Answer:

i think its -17

3 0
3 years ago
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