Question

Which equation could be solved using this application of the quadratic formula? A. -2x2 â’ 8 = 10x â’ 3 B. 3x2 â’ 8x â’ 10 = 4 C. 3x2 8x â’ 10 = -8 D. -2x2 8x â’ 3 = 4.

Answer 1

The given question can be solve using quadratic formula.

The correct option is (c) $3x^2 +8x -10=-8$.

Given:

The given equation is,

$x=\dfrac{-8\pm\sqrt{8^2-4(3)(-1)}} {2(3)}$---------------------------(1)

Write the general quadratic equation.

$ax^2 + bx +c=0$

Write the quadratic formula.

$x =\dfrac {-b \pm \sqrt{(b^2 - 4ac)} } {2a}$------------------------------- (2)

Compare equation (1) and (2).

$a=3\\b=8\\c=-2$

Substitute the value of $a$, $b$ and $c$ in general quadratic.

$3x^2 +8x -2=0$

Subtract $8$ from each side of above equation.

$3x^2 +8x -2 -8=0-8\\3x^2 +8x -10=-8$

Thus, the correct option is (c) $3x^2 +8x -10=-8$.

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