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stepan [7]
2 years ago
14

Which equation could be solved using this application of the quadratic formula? A. -2x2 â’ 8 = 10x â’ 3 B. 3x2 â’ 8x â’ 10 = 4 C

. 3x2 8x â’ 10 = -8 D. -2x2 8x â’ 3 = 4.
Mathematics
1 answer:
hodyreva [135]2 years ago
6 0

The given question can be solve using quadratic formula.

The correct option is (c) 3x^2 +8x -10=-8.

Given:

The given equation is,

x=\dfrac{-8\pm\sqrt{8^2-4(3)(-1)}} {2(3)}---------------------------(1)

Write the general quadratic equation.

ax^2 + bx +c=0

Write the quadratic formula.

x  =\dfrac {-b \pm  \sqrt{(b^2 - 4ac)} } {2a}------------------------------- (2)

Compare equation (1) and (2).

a=3\\b=8\\c=-2

Substitute the value of a, b and c in general quadratic.

3x^2 +8x -2=0

Subtract 8 from each side of above equation.

3x^2 +8x -2 -8=0-8\\3x^2 +8x -10=-8

Thus, the correct option is (c) 3x^2 +8x -10=-8.

Learn more about quadratic equation here:

brainly.com/question/17177510

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Answer:

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Step-by-step explanation:

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3 years ago
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Options (2), (4) and (5)

Step-by-step explanation:

Option (1).

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Option (2).

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Option (3).

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Option (4).

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Option (5).

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3 years ago
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I'm sure that the hypotenuse is 13 yards

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