Answer:
Question 1: y = 3/4x + 1/4.
Question 2: y = 6/5x + 7/5.
Step-by-step explanation:
Question 1: A line perpendicular to another line would have a slope that is the negative reciprocal of the other line. If the slope of the first line is -4/3, the slope of a line perpendicular to the first would have a slope of 3/4.
Since the line goes through (5, 4), we can just put the points into the equation, y = 3/4x + b.
4 = 3/4(5) + b
b + 15/4 = 4
b = 16/4 - 15/4
b = 1/4
So, the equation of the line is y = 3/4x + 1/4.
Question 2: 5x + 6y = -6
6y = -5x - 6
y = -5/6x - 1
As stated before, a line perpendicular to another will have a slope that is the negative reciprocal of the other. So, the slope of the other line is 6/5.
The line goes through (-2, -1), so we can put the points into the equation, y = 6/5x + b.
-1 = 6/5(-2) + b
b - 12/5 = -5/5
b = -5/5 + 12/5
b = 7/5
So, the equation of the line is y = 6/5x + 7/5.
Hope this helps!
Answer:
2
Step-by-step explanation:
add 1 plus 1 if you have 1 gummy and you add one you will have 2 gummies
Answer:
No.
Step-by-step explanation:
When you plug in -6 for x, and 6 for y, like this 5 (-6) + 12 (6) = -15, it does not equal -15, but 42.
Answer:
False
Step-by-step explanation:
False - one has nothing to do with the other. None of the data points can lie on the regression line,
and you can have the coeff. of determination be 0.5.
Answer:
The values of
so that
have vertical asymptotes are
,
,
,
,
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of
so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is
. Then, the vertical asymptotes associated with function cosecant are located in the values of
of the form:
, 
In other words, the values of
so that
have vertical asymptotes are
,
,
,
,
.