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3 years ago

Use the dropdown menus to write an equation with infinitely many solutions.

Mathematics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

4(2x + 3) - x = 7x + 12

Explanation:

That's what T4L/Edge said

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The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

If 3t -7 = 5t, then 6t =

USPshnik [31]

Answer:

Step-by-step explanation:

$3t-7=5t$

subtract 3t from both sides

$-7 = 2t$

multiply both sides by 3

$-21 = 6t$

so 6t = -21

5 0

2 years ago

Read 2 more answers

Whats the limit of x as x goes to 17?

SSSSS [86.1K]

Shouldn’t be 17, that’s the limit

4 0

4 years ago

What’s the answer please i don’t need work shown :)

Lady bird [3.3K]

Answer:

102

You didn't ask for work and I shall respect your wish

6 0

3 years ago

Selecting an SUV with a blue exterior

frozen [14]

The answer is straightforward, by the "rule of product":

There are

3×8×2=48

different combinations (distinct possible cars) that can be created.

There 33 choices for body style; 88 choices for exterior colors, and 22 choices of interior color schemes:

Since each of these choices are independent (the choice of body style doesn't depend on exterior or interior color, e.g.) we multiply the number of choices for each quality to obtain: 3×8×2=483×8×2=48 distinct ways to create a car

6 0

2 years ago