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3 years ago

Use the dropdown menus to write an equation with infinitely many solutions.

Mathematics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

4(2x + 3) - x = 7x + 12

Explanation:

That's what T4L/Edge said

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Solve for q.<br><br> s = 4p + 4q solve the equation

Harlamova29_29 [7]

Answer:

$q = \frac{s -4p}{4}\\$

Step-by-step explanation:

$s = 4p +4q \\ 4p +4q = s \\ 4p +4q -4p = s -4p \\ 4q = s - 4p \\ \frac{4q}{4} = \frac{s -4p}{4} \\ q = \frac{s -4p}{4}$

4 0

3 years ago

7 whole number 2/3 -4 5/6 + 2 3/8

denis-greek [22]

Im not sure ask ur teacher

4 0

2 years ago

Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p

DedPeter [7]

Answer:

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Where,

$\bar x_1$ = sample meaan of population 1

$\bar x_2$ = sample mean of population 2

$n_1$ = sample size of population 1

$n_2$ = sample size of population 2

Therefore, this is the test

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

7 0

3 years ago

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

3 0

3 years ago

Which of the following shows the correct evaluation for the exponential expression 6 over 7 to the power of 2?

yaroslaw [1]

For this case we have the following expression:
6 over 7 to the power of 2
(6/7) ^ 2
By power properties we can rewrite the expression as:
(6/7) * (6/7)
Calculating we have:
(6/7) * (6/7) = 36/49
Answer:
6 over 7 times 6 over 7 equals 36 over 49

5 0

3 years ago