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xeze [42]
2 years ago
13

Help pleaseeeeeeeeeeeeee

Mathematics
1 answer:
Vlada [557]2 years ago
3 0


Here is answer in the picture I hope this will help to you

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Write a polynomial equation of degree 3 such that two of its roots are 2 and an imaginary number
natta225 [31]
(x-2)(x^2+1)=x^3+x-2x^2-2=x^3-2x^2+x-2
5 0
3 years ago
A scale drawing of a school bus has a scale of 1/2 inch to 5feet. If the length of the school bus is 4 1/2 inches on the scale d
Sedaia [141]
Answer: actual length = 45 ft

Explanation:

Scale drawn:

1/2 inch = 5ft

Meaning that if the drawing scale is 0.5 inch then the actual bus would be 5ft.

If the length of the drawn school bus is 4 1/2 inches. We can write:

1/2 = 5
4 1/2 = x

=> x = (5 x 4 1/2)/1/2
Or x = (5 x 4.5)/0.5
x = 22.5/0.5
x = 45

Therefore the actual length of the bus is 45 ft

3 0
3 years ago
EXREAMLY URGENT!! WILL FOREVER THANK YOU!!!! PLS JUST TAKE A LOOK!!!!! 1. What is the ratio of the sides of triangle XYZ?
sdas [7]

Answer:

Dear Laura Ramirez

Answer to your query is provided below

The ratio of triangle XYZ is 1:√3 :2.

Step-by-step explanation:

A 30-60-90 right triangle (literally pronounced "thirty sixty ninety") is a special type of right triangle where the three angles measure 30 degrees, 60 degrees, and 90 degrees. The triangle is significant because the sides exist in an easy-to-remember ratio: 1:√3 :2.

7 0
2 years ago
If sin 115° ≈ 0.91 and cos 115° = -0.42, then sin -115° =
EastWind [94]

Answer:

sin -115° = -0.91

Step-by-step explanation:

Point A is (cos 115°, sin 115°). Since cos 115° = -0.42 and sin 115° ≈ 0.91, it means that the coordinates at point A is (-0.42, 0.91).

As for point B which was revolved around -115°,

the coordinates will be similar to point A but you just have to change the negative.

B(cos -115°, sin -115°) = B(0.42, -0.91)

3 0
3 years ago
How many solutions does this equation have? 12 + 2x 2 = 13 A) no solution B) exactly one solution C) exactly two solutions D) in
Yakvenalex [24]

Answer:b

Step-by-step explanation:

8 0
3 years ago
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