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vaieri [72.5K]
3 years ago
10

Find the slope of the line that passes through the points (2, 4) and (6, 12).

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

slope of the line passing through these coordinates is 2

Step-by-step explanation:

slope of line :-

=》

\frac{y2 - y1}{x2 - x1}

=》

\frac{12 - 4}{6 - 2}

=》

\frac{8}{4}

=》

2

so, the slope of the line is 2

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Answer:

a) 183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

b) 190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a : Summer

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

Part b: Winter

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

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Plz help me with my home work and explain too plz asap
mrs_skeptik [129]
If you cut it into three pieces, it's easier to understand how to do it, as I show in the picture. when you are done splitting this into three parts you start multiplying. The side bases' digits are 31*23=713 and you need to do that twice, so 713+713=1,426. Next, you find the side-length for, and multiply, the middle base which is 23*19=437. Finally, you add all of that together 1,426+437=1,863.

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3 years ago
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