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2 years ago

29 = v+17 what the answer cs ion get it

Mathematics

1 answer:

Alexus [3.1K]2 years ago

6 0

Answer:

Step-by-step explanation:

29 = v + 17

29 - 17 = v

12 = v

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Which of the following transformations will result in a similar figure?

iren [92.7K]

Answer:

Step-by-step explanation:the answer is b hope this helps sorry if not right

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3 years ago

Of all rectangles with a perimeter of 7, which one has the maximum area? (give the dimensions.)

Elena L [17]

The rectangle with maximum area will actually be a square.

Each side will be of length 7/4 = 1 3/4.

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3 years ago

Multiple Choice The opposite of –4 is A. 4. B. –4. C. –(–(–4)). D. –|4|.

joja [24]

Answer:

a. 4

Step-by-step explanation:

-1(-4) = 4

7 0

3 years ago

Read 2 more answers

The graph is shown for the equation y = –x + 4.

ivann1987 [24]

Answer:

Option C. $y=-\frac{1}{2}(2x-8)$

Step-by-step explanation:

we know that

If a system of two linear equations has an infinite number of solutions, then both equations must be identical

The given equation is

$y=-x+4$

<u><em>Verify each case</em></u>

Option A. we have

$y=-4(x+1)$

apply distributive property

$y=-4x-4$

Compare with the given equation

$-x+4 \neq -4x-4$

Option B. we have

$y=-(x+4)$

remove the parenthesis

$y=-x-4$

Compare with the given equation

$-x+4 \neq -x-4$

Option C. we have

$y=-\frac{1}{2}(2x-8)$

apply distributive property

$y=-x+4$

Compare with the given equation

$-x+4=-x+4$

therefore

This equation with the given equation form a system that has an infinite number of solutions

Option D. we have

$y=x+4$

Compare with the given equation

$-x+4 \neq x+4$

7 0

3 years ago

The region bounded by y=5/x, y=0, x=1, and x=3 is rotated about the x-axis. find the volume of the resulting solid.

brilliants [131]

Volume of Revolution = $\pi \int\limits^b_a {y^{2}} \, dx$
Volume of Revolution = $\pi \int\limits^3_1 { (\frac{5}{x})^{2}} \, dx$
= $\pi \int\limits^3_1 ({\frac{25}{x^{2}}) \, dx$
= $25\pi \int\limits^3_1 ({\frac{1}{x^{2}}) \, dx$
= $25\pi \int\limits^3_1 ({x^{-2}}) \, dx$
= $25\pi \ ^{3} [-x^{-1}] _{1} 
$
$= 25\pi\ ((-1/3) - (-1/1)) \\
= 25\pi\ (2/3) \\
= 50/3 \pi\ units^{3}$

6 0

4 years ago