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3 years ago

Use the diagram. AB is a diameter, and AB is perpendicular to CD. The figure is not drawn to scale.

Mathematics

1 answer:

Westkost [7]3 years ago

7 0

Answer:

The measure of arc BD is 147°

Step-by-step explanation:

we know that

If segment AB is perpendicular to segment CD

then

The measure of the inner angle CPA is a right angle (90 degrees)

Remember that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

m∠CPA=(1/2)[arc AC+arc BD]

substitute the given values

90°=(1/2)[33°+arc BD]

180°=33°+arc BD

arc BD=180°-33°=147°

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What is the integers from 25 to 41

DedPeter [7]

It is the sum of the integers from 1-41 minus the sum of the integers from 1-24 divided by 17 the sum of the integers from 1-41 is (42)(45)/2 = 861 the sum of the integers from 1-24 is (24)(25)/2 = 300 (861-300)/17 = 33 The answer is 33

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3 years ago

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PLEAZE HELP IM FAILING THIS CLASS 9) The volume of a box is represented by x' +11x² + 20x – 32. The width of the box is x – 1, a

In-s [12.5K]

Answer:

Step-by-step explanation:

Volume of the box = x³ +11x² + 20x – 32 I think the ' is a typo for ³

the width is x-1 and the height is x+8

Find an expression for the length

Vol = LWH solve L

Vol / (WH) = L so

L = (x³ +11x² + 20x – 32) / (x-1) (x+8)

so it would help to factor the numerator

(x³ +11x² + 20x – 32) I'm willing to bet (x-1) and (x+8) are factors

but I will plot the equation to find the three roots

(x³ +11x² + 20x – 32) = (x-1) (x+8) (x+4)

L = (x³ +11x² + 20x – 32) / (x-1) (x+8)

= (x-1) (x+8) (x+4) / (x-1) (x+8) the (x-1) and (x+8) cancel out leaving

L = (x + 4)

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3 years ago

What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)

Ann [662]

Answer:

The midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

Step-by-step explanation:

Given points are $(-2,-2)\ and\ (4,6)$ . We need to find the midpoint of the line segment.

The formula of finding midpoints between the point $(x_1,y_1)\ and\ (x_2,y_2)$ is

$(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)$

W have points $(x_1,y_1)=(-2,-2)$ . And $(x_2,y_2)=(4,6)$

Let us plug the value in Equation (1)

$(\frac{-2+4}{2} ),(\frac{-2+6}{2})$

$(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)$

So, the midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .

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3 years ago

Determine the range of the function.

HACTEHA [7]

Answer is A all real numbers

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3 years ago

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Leokris [45]

Answer:

C - Rhombus

Step-by-step explanation:

A rhombus ALWAYS has perpendicular diagonals. A rhombus is just a parallelogram with four equal sides, so two of them have to be parallel, at least.

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3 years ago

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