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andrezito [222]
2 years ago
11

A solution contains 8% salt. How much pure water should be added to 25 ounces of the solution to dilute it to a 3% solution? Rou

nd to the nearest hundredth if needed.
Mathematics
1 answer:
lidiya [134]2 years ago
8 0

41.67 ounce of pure water should be added to 25 ounces of the 8% salt solution to dilute it to a 3% solution

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of pure water needed to dilute the solution. Hence:

8% * 25 = 3% * (x + 25)

2 = 0.03x + 0.75

x = 41.67 ounce

41.67 ounce of pure water should be added to 25 ounces of the 8% salt solution to dilute it to a 3% solution

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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52 is not a perfect square, so the root will be a decimal
Rad 52 = 7.2
The square root of 52 is 7.2
Hope this helps!
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Emery earns money mowing his neighbors' lawns. He charges $1.25 per square yard for each lawn he mows. His neighbors, the Flores
aleksandr82 [10.1K]

Answer: 4.2 yards

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Let x = length of the Flores' lawn in yards.

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Charge per square yard = $1.25

Charge for Flores lawn = 1.25 × (Area of lawn)

= 1.25 (4x)

= 5x

As per given,

5x=21\\\\\Rightarrow\ x=\dfrac{21}{5}\\\\\Rightarrow\ x=4.2

Hence, the length of the Flores's lawn = 4.2 yards

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3 years ago
Square root of 50 + square root of 72
MakcuM [25]
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5 0
4 years ago
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Can someone show me how to do this? It’s dividing polynomials.
Kisachek [45]

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5 0
3 years ago
Kids bought a package with 2 9/ 16 lb of ground meat to make hamburgers he was he has 2/5 pound of ground meat left about how ma
poizon [28]

Answer:

The quantity of ground meat he use for hamburgers is                                   2 \frac{13}{80} pounds

Step-by-step explanation:

Given as :

The total quantity of ground meat bought to make hamburgers = 2 \frac{9}{16}

Or, The total quantity of ground meat bought to make hamburgers = \frac{41}{16} pound

The quantity of ground meat left after use = \frac{2}{5} pound

Now, let The quantity of ground meat used for hamburgers = x pound

So, x = The total quantity of ground meat bought - The quantity of ground meat left

Or, x = \frac{41}{16} pound -  \frac{2}{5} pound

Or, x =  \frac{205-32}{80} pound

I.e x = \frac{173}{80}

∴  x = 2 \frac{13}{80} pounds

Hence The quantity of ground meat he use for hamburgers is                        2 \frac{13}{80} pounds  . Answer

7 0
4 years ago
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