35. the set, s consists of 900,000,000 whole numbers, each being the same number of digits long. howmany digits long is a number from s? (hint: use the fact that a whole number cannot start with the digit 0.)
1 answer:
Answer:
Let the number of digits be n and the number of elements in set be s .
<h3>When n = 1</h3>
The set contains 1-digit numbers, 1 through 9, The set consists of 10 - 1 = 9 numbers.
<h3>When n = 2</h3>
The set contains 2-digit numbers, 10 through 99, The set contains 100 - 10 = 90 numbers.
<h3>When n = 3</h3>
The set contains 3-digit numbers, 100 through 999, The set contains 1000 - 100 = 900 numbers.
The pattern we see helps us determine the relationship between s and n as follows.
When set contains n-digit numbers, the set contains:
s = 10ⁿ - 10ⁿ⁻¹ = 10ⁿ⁻¹(10 - 1) = 9*10ⁿ⁻¹ elements
We have s known , substitute it into equation above and solve for n :
900000000 = 9*10ⁿ¹ 100000000 = 10ⁿ⁻¹ 10⁸ = 10ⁿ⁻¹ n - 1 = 8 n = 9
The numbers in the set s are 9-digit long.
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Step-by-step explanation:
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