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svetlana [45]
2 years ago
7

Given that ∠STV = 108° and ∠RST = 50°, determine the missing angles:

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
7 0
A. 108 degrees
b. 72 degrees
c. 108 degrees

Hope this helps :)
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it's a right angled triangle

it's also a scalene triangle because not all sides are equal

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jada is using a computer’s random number generator to produce 6 random whole numbers between 1 and 100 so she can use a random s
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The random numbers are selected randomly. Just because they happen to be 6 numbers in a row does not mean that they were not. If she is confident in the random number generator, which can be assumed, then the random numbers were still randomly selected and can be used. To regenerate would be a mistake because Jada is then picking and choosing which random numbers are chosen, defeating the purpose of a random number generator

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There once was a
r-ruslan [8.4K]
I am pretty sure the only way to do this is: 

• To bring the corn first

• To bring the goose second

• To bring the dog third

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4 years ago
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Five cards (a hand) are dealt from a randomly shuffled deck of cards. For those of you that are not familiar with playing cards:
sp2606 [1]

Answer: 0.0004951

Step-by-step explanation:

Given

Five cards are from the deck

The total number of cards in the deck is 52

total spades card is 13

We have to choose 5 cards out of 13, this can be done in

\Rightarrow ^{13}C_5

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\Rightarrow P=\dfrac{^{13}C_5}{^{52}C_5}\\\\\Rightarrow P=\dfrac{1287}{2598960}=0.0004951

4 0
3 years ago
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0
2 years ago
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