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wolverine [178]

3 years ago

10

A map shows the road between the cities of Saxon and Melbeck. If the distance on the map between the two cities is 7 inches, wha

t is the real distance? The scale is 2 inch:5 miles.

1 answer:

goblinko [34]3 years ago

6 0

Answer:

17.5

Step-by-step explanation:

2:5

7 divided by 2 is 3.5

The difference is 3.5, now times each side by 3.5

7 inches:17.5 miles

You might be interested in

19.95 rounded in math

Gnoma [55]

It would be rounded to 20.

hope this helps you

8 0

4 years ago

Read 2 more answers

At the end of the study, the sociologist had a sample of 500 expectant parents. He estimates that there are 6 million expectant

sertanlavr [38]

If at the end of the study, the sociologist had a sample of 500 expectant parents and he estimates that there are 6 million expectant parents in the United States then the value of n is 500.

Given that the sample size is 500 and the number of expectant parents be 6 million.

We are required to find what n represents and value of n.

The value of n is 500. Small n shows the sample size and capital N shows the size of population.

Sample is that part of the population that represents the characteristics of the whole population.

Population is the number of individuals present in the area which a researcher wants to observe.

Hence if at the end of the study, the sociologist had a sample of 500 expectant parents and he estimates that there are 6 million expectant parents in the United States then the value of n is 500.

Learn more about sample at brainly.com/question/24466382

#SPJ4

6 0

1 year ago

Is my answer correct

Leto [7]

mayhaps it is right and wrong is subjective

4 0

3 years ago

Give that T = 37v/6v-5.4m a. Make V the subject of relation b. If T = 4.5 and M =7x10(7),calculate the value of v , leaving your

PilotLPTM [1.2K]

Answer:

$v = \frac{5.4mT}{6T - 37}$

$v = -1.701*10^8$

Step-by-step explanation:

Given

$T = \frac{37v}{6v-5.4m}$

Solving (a): Make v the subject

$T = \frac{37v}{6v-5.4m}$

Cross Multiply:

$(6v-5.4m)T = 37v$

Open bracket

$6vT - 5.4mT = 37v$

Collect Like terms

$6vT - 37v= 5.4mT$

Factorize:

$(6T - 37)v= 5.4mT$

Make v the subject

$v = \frac{5.4mT}{6T - 37}$

Solving (b):

$T = 4.5$

$m = 7 * 10^7$

So, the expression becomes:

$v = \frac{5.4mT}{6T - 37}$

$v = \frac{5.4*7*10^7*4.5}{6*4.5 - 37}$

$v = \frac{170.1*10^7}{27 - 37}$

$v = \frac{170.1*10^7}{-10}$

$v = -17.01*10^7$

$v = -1.701*10*10^7$

$v = -1.701*10^8$

6 0

3 years ago

Absolute value of (0, -4/5)

Crazy boy [7]

To answer this question, we need to know what absolute value is in the first place. <u><em>ANSWERS ARE AT THE BOTTOM.</em></u>

Absolute value represents how far something is from 0 in a number line.

For example, lets take 4.

4 is 4 units away from 0 on the number line, so the absolute value of 4 is 4.

Now lets look at another example, -4. -4 is also 4 units away from 0, just in the other direction. However, when calculating absolute value, we do not care about the direction. Therfore, the absolute value of -4 is also 4.

Now let's look at your problem.

You want the <em>absolute value</em> of 0 and -4/5

<u><em>Following the same principle above about the distance from 0, here are your answers:</em></u>

<u><em></em></u>

<u><em>Absolute value of 0</em></u><u><em>: </em></u><em>0</em>

<em></em>

<u><em>Absolute value of -4/5</em></u><u><em>: </em></u><em>4/5</em>

8 0

2 years ago